When looking into which team goes the furthest without suffering a loss in the regular season, it’s important to not solely focus on their first game or so, but instead, their first six or seven. It may not be ideal if your team has to play in New Orleans for game one, but if they have a stretch of winnable home games to follow, it’s worth taking that week one risk (if the price is right). Here is my pick to go the furthest in the 2019 NFL season without taking an ‘L’ (sorry if the picture is misleading Miami fans…):
New England Patriots @ +750
The Patriots are the favorites and generally that’d concern me, but in this spot they just look too good considering their early season schedule. In their first game they’re lined at -6 to beat the Steelers, then following on from that they have some very favorable match-ups, all the way until they play on the road to Philly in week eleven.
Their schedule up until then is:
1. Pittsburgh Steelers
2. @ Miami Dolphins
3. New York Jets
4. @ Buffalo Bills
5. @ Washington Redskins
6. New York Giants
7. @ New York Jets
8. Cleveland Browns
9. @ Baltimore Ravens
Cleveland could be troublesome, depending on how they play this season, and Baltimore could be tricky on the road, but realistically they should be favorites for all these games unless they have an uncharacteristic collapse. One thing that does hinder them for this bet is the lack of an early bye week, but even still, +750 is certainly worth a play.
1u – New England Patriots To The Last Undefeated Team In The NFL Regular Season @+750